Car pooling

We will sort the trips by the starting point. Then we will iterate over the trips and for each trip we will add the number of passengers to the current number of passengers. If the current number of passengers is greater than the capacity, we will return False. Otherwise, we will return True.

class Solution:
    def carPooling(self, trips: List[List[int]], capacity: int) -> bool:
        lst = []
        for n, start, end in trips:
            lst.append((start, n))
            lst.append((end, -n))
        lst.sort()

        pas = 0
        for loc in lst:
            pas += loc[1]
            if pas > capacity:
                return False
        return True

Time complexity: O(nlogn)
Space complexity: O(n)