Find duplicate file in system

We will iterate over each path, extract the content, and based on the content, we will attach it to a hashmap where the key will be the content. Then we filter out the single files and return the rest as result.

class Solution:
    def findDuplicate(self, paths: List[str]) -> List[List[str]]:
        fileName = collections.defaultdict(list)
        result = []

        for path in paths:
            filePath = path.split()
            for idx in range(1, len(filePath)):
                i = filePath[idx].index('(')
                word = filePath[idx][i:]
                value = filePath[0] + '/' + filePath[idx][:i]
                fileName[word].append(value)

        for key, value in fileName.items():
            if len(fileName[key]) > 1: 
                result.append(value)

        return result

Time Complexity: O(n)
Space Complexity: O(n)