Fizz buzz

We will iterate over the numbers from 1 to n and append the corresponding string to the result list. If the number is divisible by 3, we will append "Fizz" to the result list. If the number is divisible by 5, we will append "Buzz" to the result list. If the number is divisible by both 3 and 5, we will append "FizzBuzz" to the result list. If the number is not divisible by 3 or 5, we will append the number to the result list.

class Solution:
    def fizzBuzz(self, n: int) -> List[str]:
        res = []
        for i in range(1, n+1):
            if i % (3*5) == 0:
                res.append("FizzBuzz")
            elif i % 3 == 0:
                res.append("Fizz")
            elif i % 5 == 0:
                res.append("Buzz")
            else:
                res.append(str(i))
        return res

Time complexity: O(n), n is the number
Space complexity: O(1)