Problem URL: Rectangle area

We will find the area of the first rectangle and the second rectangle. We will find the area of the overlapping rectangle by finding the length and breadth of the overlapping rectangle. We will subtract the area of the overlapping rectangle from the area of the first rectangle and the area of the second rectangle and add the area of the overlapping rectangle to get the total area.

class Solution:
    def computeArea(self, ax1: int, ay1: int, ax2: int, ay2: int, bx1: int, by1: int, bx2: int, by2: int) -> int:
        area1 = (ax2-ax1)*(ay2-ay1)
        area2 = (bx2-bx1)*(by2-by1)
        length = min(ax2, bx2) - max(ax1, bx1)
        breadth = min(ay2, by2) - max(ay1, by1)

        if length > 0 and breadth > 0:
            area3 = length*breadth
        else:
            area3 = 0
        return area1+area2-area3

Time complexity: O(1)
Space complexity: O(1)

We can also achieve the same thing in one line code-

class Solution:
    def computeArea(self, ax1: int, ay1: int, ax2: int, ay2: int, bx1: int, by1: int, bx2: int, by2: int) -> int:
        return (ax2-ax1)*(ay2-ay1) + (bx2-bx1)*(by2-by1) - max(0, min(ax2, bx2) - max(ax1, bx1)) * max(0, min(ay2, by2) - max(ay1, by1))