Problem URL: XOR operation in an array

We will generate the array and then XOR all the elements.

class Solution:
    def xorOperation(self, n: int, start: int) -> int:
        res = 0
        for i in range(n):
            num = start + 2*i
            res ^= num
        return res

Time complexity: O(n)
Space complexity: O(1)

We can also use reduce function to XOR all the elements.

class Solution:
    def xorOperation(self, n: int, start: int) -> int:
        return reduce(lambda x, y: x ^ y, [start + 2*i for i in range(n)])