Max consecutive ones

We will count the number of consecutive ones and update the result if it is greater than the current result.

class Solution:
    def findMaxConsecutiveOnes(self, nums: List[int]) -> int:
        count, res = 0, 0

        for num in nums:
            if num == 1:
                count += 1
                res = max(res, count)
            else:
                count = 0

        return res

Time complexity: O(n)
Space complexity: O(1)