Sum of number and its reverse

We will try every number till the original given number, reverse the number and add it to the original number.

class Solution:
    def sumOfNumberAndReverse(self, num: int) -> bool:
        for i in range(num+1):
            if i + int(str(i)[::-1]) == num:
                return True
        return False

Time complexity: O(n)
Space complexity: O(1)